class 8th math english medium annual exam paper 2026 answer

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Class 8th Math English Medium Annual Exam Paper 2026 – Question Paper & Solution यहाँ देखें

कक्षा 8वीं वार्षिक परीक्षा 2026 के अंतर्गत Math (English Medium) का पेपर जल्द ही आयोजित होने वाला है। बहुत से छात्र अभी से गूगल पर सर्च कर रहे हैं जैसे class 8th math english medium annual exam paper 2026, class 8 maths paper 2026 solution, kaksha 8 ganit english medium question paper। इसीलिए इस आर्टिकल में आपको पहले से जानकारी दी जा रही है कि जैसे ही पेपर होगा, उसी दिन से इस पेपर का full solution और question paper यहाँ अपडेट कर दिया जाएगा।

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Class 8th Maths Paper 2026 Solution Update

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Class 8 Math Question Paper 2025-26 (Bilingual with Solutions)

E2026MTH08467

Rajya Shiksha Kendra M.P., Bhopal

Annual Examination Session – 2025-26

Subject – Mathematics

Time – 2 ½ hours. Class – 8 M.M. – 60
Multiple Choice Questions (Question 1 to 5)
Instructions- Choose and write the correct answer. Each question carries 1 mark.
Q.1 A quadrilateral in which two separate pairs of adjacent sides are equal in length is- 1
  • (A) Square
  • (B) Rectangle
  • (C) Kite ✔
  • (D) Rhombus
Solution: A kite has two distinct consecutive pairs of sides of equal length.
Q.2 On tossing a coin the probability of getting a tail is- 1
  • (A) 1/2 ✔
  • (B) 2
  • (C) 1
  • (D) 0
Solution: Total outcomes = 2 (Head, Tail). Favorable outcome (Tail) = 1. Probability = 1/2.
Q.3 Square root of 5929 is- 1
  • (A) 72
  • (B) 77 ✔
  • (C) 78
  • (D) 75
Solution: 77 × 77 = 5929. Therefore, √5929 = 77.
Q.4 The digit at the unit place of cube of 23 is- 1
  • (A) 7 ✔
  • (B) 6
  • (C) 3
  • (D) 9
Solution: Unit digit of 23 is 3. Cube of 3 = 3 × 3 × 3 = 27. So, unit digit is 7.
Q.5 If the Square of a number is 7225 then the number will be- 1
  • (A) 75
  • (B) 80
  • (C) 85 ✔
  • (D) 95
Solution: 85 × 85 = 7225. Thus, √7225 = 85.
Fill in the blanks (Question 6 to 10)
Instruction- Each question carries 1 mark.
Q.6 A closed figure made by line segments is called Polygon.1
Q.7 A Pie (or Circle) graph shows the relationship between a whole and its parts.1
Q.8 Square of 1 is always 1.1
Q.9 Sales / GST tax is charged on the sale of an item by the government.1
Q.10 The pictorial representation of data using symbols is called Pictograph.1
Very Short Answer Type Questions (Question 11 to 16)
Instructions- Answer the following questions in one word/sentence. Each question carries 2 marks.
Q.11 Find the value: (-5 / 4) ÷ (3 / 7)2
Solution:
= (-5 / 4) × (7 / 3)
= (-5 × 7) / (4 × 3)
= -35 / 12
Q.12 Solve the equation: 2x – 2 = 62
Solution:
2x = 6 + 2
2x = 8
x = 8 / 2 ⇒ x = 4
Q.13 Write the exponential form of 16.2
Solution:
16 = 2 × 2 × 2 × 2 = 24 (or 42)
Q.14 Write perfect square numbers between numbers 40 and 100.2
Solution:
The perfect squares between 40 and 100 are:
72 = 49
82 = 64
92 = 81
Q.15 Find the value of (-4)3.2
Solution:
(-4)3 = (-4) × (-4) × (-4) = -64
Q.16 Which graph represent the relationship between dependent variable and independent variable?2
Solution:
A Line Graph represents the relationship between a dependent and an independent variable.
Short Answer Type Questions (Question 17 to 22)
Instructions : Answer the following questions. Each question carries 3 marks.
Q.17 Find the value-
(-3 / 4) × { (2 / 3) × (-5 / 6) }3
Solution:
First, solve the brackets:
(2 / 3) × (-5 / 6) = -10 / 18 = -5 / 9
Now multiply:
= (-3 / 4) × (-5 / 9)
= 15 / 36
= 5 / 12
Q.18 Solve the Equation ?
5x + 4 = 24 + 3x3
Solution:
5x – 3x = 24 – 4
2x = 20
x = 20 / 2 ⇒ x = 10
Q.19 Find the Smallest number by which 256 must be multiplied to obtain a perfect cube.3
Solution:
Prime factorization of 256:
256 = (2 × 2 × 2) × (2 × 2 × 2) × 2 × 2
Here, one triplet is incomplete (we only have two 2’s).
To make it a perfect cube, we need to multiply by one more 2.
Smallest number = 2
Q.20 Out of 25 students 72% students like Mathematics. Find the number of students who like Mathematics.3
Solution:
Total students = 25
Students who like Math = 72% of 25
= (72 / 100) × 25
= 72 / 4
= 18 students
Q.21 Using the table given below, draw a line graph showing the relationship between length of a side and perimeter of a square.3
Length of side (in cm) 2 3 4 5
Perimeter (in cm) 8 12 16 20
Solution / Graph Instructions:
Draw X-axis and Y-axis on graph paper.
1. Take Length of side on the X-axis (Scale: 1 unit = 1 cm). Mark points 1, 2, 3, 4, 5.
2. Take Perimeter on the Y-axis (Scale: 1 unit = 4 cm). Mark points 4, 8, 12, 16, 20.
3. Plot coordinates: (2, 8), (3, 12), (4, 16), and (5, 20).
4. Join the points. You will get a straight linear graph passing through the origin.
Q.22 Find the value of 852 using “Ekadhiken poorven” method.3
Solution:
In Vedic math for numbers ending in 5:
Number = 85
Left part = 8 × (8 + 1) = 8 × 9 = 72
Right part = 5 × 5 = 25
Combining both: 7225
Long Answer Type Questions (Question 23 to 26)
Instructions : Answer the following questions. Each question carries 5 marks.
Q.23 Multiply (a2 + 2b2) and (5a – 3b).5
Solution:
= (a2 + 2b2)(5a – 3b)
Distribute terms:
= a2(5a – 3b) + 2b2(5a – 3b)
= 5a3 – 3a2b + 10ab2 – 6b3
= 5a3 – 3a2b + 10ab2 – 6b3
Q.24 How much cloth will be needed to cover a suitcase of dimensions 80cm × 48cm × 24cm.5
Solution:
Cloth required = Total Surface Area (TSA) of the suitcase.
l = 80 cm, b = 48 cm, h = 24 cm
TSA = 2(lb + bh + hl)
= 2(80×48 + 48×24 + 24×80)
= 2(3840 + 1152 + 1920)
= 2(6912)
= 13824 cm2
So, 13824 cm2 of cloth is needed.
Q.25 The length of shadow of 14 m long pole on ground is 10 meter under similar conditions find the length of a tree whose shadow is 15 meter long.5
Solution:
This is a case of direct proportion.
Height of pole / Shadow of pole = Height of tree / Shadow of tree
Let tree height be x meters.
14 / 10 = x / 15
Cross multiplying: 10 × x = 14 × 15
10x = 210
x = 210 / 10 = 21 m
The length (height) of the tree is 21 meters.
Q.26 Factorize?
3m2 + 9m + 65
Solution:
3m2 + 9m + 6
Take 3 common:
= 3(m2 + 3m + 2)
Split middle term (3m = 2m + 1m):
= 3(m2 + 2m + 1m + 2)
= 3[m(m + 2) + 1(m + 2)]
= 3(m + 1)(m + 2)

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